0=4t^2+275t-1925

Solution for 0=4t^2+275t-1925 equation:

0=4t^2+275t-1925

We move all terms to the left:

0-(4t^2+275t-1925)=0

We add all the numbers together, and all the variables

-(4t^2+275t-1925)=0

We get rid of parentheses

-4t^2-275t+1925=0

a = -4; b = -275; c = +1925;
Δ = b2-4ac
Δ = -2752-4·(-4)·1925
Δ = 106425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{106425}=\sqrt{225*473}=\sqrt{225}*\sqrt{473}=15\sqrt{473}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-275)-15\sqrt{473}}{2*-4}=\frac{275-15\sqrt{473}}{-8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-275)+15\sqrt{473}}{2*-4}=\frac{275+15\sqrt{473}}{-8}
$